标题 | Validate Binary Search Tree |
通过率 | 21.9% |
难度 | 中等 |
Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than the node's key.
- Both the left and right subtrees must also be binary search trees.
confused what "{1,#,2,3}"
means?
本题就是确定一棵树是否为二叉排序树,左<中<右,可以用中序遍历去判断,也可以用一个范围值去判断当前节点是否在其中,范围的下界是左边的树,范围的右界是右边的树,直接看代码了:
1 /** 2 * Definition for binary tree 3 * public class TreeNode { 4 * int val; 5 * TreeNode left; 6 * TreeNode right; 7 * TreeNode(int x) { val = x; } 8 * } 9 */10 public class Solution {11 public boolean isValidBST(TreeNode root) {12 return isBst(root,Long.MIN_VALUE,Long.MAX_VALUE);13 }14 public boolean isBst(TreeNode root,long min,long max){15 if(root==null) return true;16 if(root.val<=min||root.val>=max)return false;17 return isBst(root.left,min,root.val)&&isBst(root.right,root.val,max);18 19 }20 }